10v^2-11v-8=0

Solution for 10v^2-11v-8=0 equation:

10v^2-11v-8=0

a = 10; b = -11; c = -8;
Δ = b2-4ac
Δ = -112-4·10·(-8)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-21}{2*10}=\frac{-10}{20}
=-1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+21}{2*10}=\frac{32}{20}
=1+3/5
$